# Write the net ionic equation for the following reaction. Cu(ClO4)2(aq) + K2CO3(aq) arrow CuCO3(s)...

## Question:

Write the net ionic equation for the following reaction.

{eq}Cu(ClO_4)_2(aq) + K_2CO_3(aq) \to CuCO_3(s) + 2KClO_4(aq) {/eq}

## Copper(II) Carbonate

• Copper(II) carbonate is also known as cupric carbonate.
• It is an ionic compound formed by the reaction between copper(II) chlorate and potassium carbonate.
• It is soluble in water.

Given the molecular equation:

{eq}\rm Cu{\left( {Cl{O_4}} \right)_2}\left( {aq} \right) + {K_2}C{O_3}\left( {aq} \right) \to CuC{O_3}\left( s \right) + 2KCl{O_4}\left( {aq} \right) {/eq}

First, convert the whole molecular equation into a complete ionic equation:

{eq}\rm C{u^{2 + }}\left( {aq} \right) + 2ClO_4^ - \left( {aq} \right) + 2{K^ + }\left( {aq} \right) + CO_3^{2 - }\left( {aq} \right) \to CuC{O_3}\left( s \right) + 2{K^ + }\left( {aq} \right) + 2ClO_4^ - \left( {aq} \right) {/eq}

Removing common ions (ions spectators) on both sides of the equation that are in an aqueous medium, the net ionic equation will be:

{eq}\boxed{\rm C{u^{2 + }}\left( {aq} \right) + CO_3^{2 - }\left( {aq} \right) \to CuC{O_3}\left( s \right)} {/eq}