Write the molecular equation, complete ionic equation, and net ionic equation for the reaction...

Sodium hydroxide (NaOH) reacts with acetic acid {eq}\rm (CH_3CO_2H) {/eq} to produce sodium acetate {eq}\rm (NaCH_3CO_2) {/eq} and water {eq}\rm (H_2O) {/eq}. It is an example of a neutralization reaction. The corresponding balanced molecular equation (phases included) is shown below:

{eq}\rm NaOH(aq)+CH_3CO_2H(aq)\to NaCH_3CO_2(aq)+H_2O(l) {/eq}

Both {eq}\rm NaOH\;and\;NaCH_3CO_2 {/eq} are strong electrolytes. Hence, they dissociate completely in water. So, the corresponding complete ionic equation is shown below:

{eq}\rm Na^+(aq)+OH^-(aq)+CH_3CO_2H(aq)\to Na^+(aq)+CH_3CO_2^-(aq)+H_2O(l) {/eq}

In the above equation, {eq}\rm Na^+ {/eq} remains present as a spectator ion. So, excluding the spectator ion, the corresponding net ionic equation is written below:

{eq}\rm CH_3CO_2H(aq)+OH^-(aq)\to CH_3CO_2^-(aq)+H_2O(l) {/eq}