# Write the molecular equation, complete ionic equation, and net ionic equation for the reaction...

## Question:

Write the molecular equation, complete ionic equation, and net ionic equation for the reaction that occurs between sodium hydroxide and acetic acid.

## Molecular, Complete Ionic, and Net Ionic Equation:

The representation of a chemical equation can be done in three possible ways: (1) molecular equation (showing the molecules of reactants and products), (2) complete ionic (showing the constituting ions of reactants and products), and (3) net ionic (showing only the active ions of reactants and products).

Sodium hydroxide (NaOH) reacts with acetic acid {eq}\rm (CH_3CO_2H) {/eq} to produce sodium acetate {eq}\rm (NaCH_3CO_2) {/eq} and water {eq}\rm (H_2O) {/eq}. It is an example of a neutralization reaction. The corresponding balanced molecular equation (phases included) is shown below:

{eq}\rm NaOH(aq)+CH_3CO_2H(aq)\to NaCH_3CO_2(aq)+H_2O(l) {/eq}

Both {eq}\rm NaOH\;and\;NaCH_3CO_2 {/eq} are strong electrolytes. Hence, they dissociate completely in water. So, the corresponding complete ionic equation is shown below:

{eq}\rm Na^+(aq)+OH^-(aq)+CH_3CO_2H(aq)\to Na^+(aq)+CH_3CO_2^-(aq)+H_2O(l) {/eq}

In the above equation, {eq}\rm Na^+ {/eq} remains present as a spectator ion. So, excluding the spectator ion, the corresponding net ionic equation is written below:

{eq}\rm CH_3CO_2H(aq)+OH^-(aq)\to CH_3CO_2^-(aq)+H_2O(l) {/eq}