Write the balanced ionic equation for the following reaction: {eq}\displaystyle \rm Sn(OH)_2(s) + OH^- (aq) \to {/eq}
Question:
Write the balanced ionic equation for the following reaction: {eq}\displaystyle \rm Sn(OH)_2(s) + OH^- (aq) \to {/eq}
Chemical Formulas:
{eq}\displaystyle \rm Sn(OH)_2(s) {/eq} is the chemical formula of tin(II) hydroxide. It is an ionic compound and the oxidation number of tin in this compound is +2. {eq}\displaystyle \rm OH^- (aq) {/eq} is the chemical formula of hydroxide ions.
Answer and Explanation: 1
The reaction between tin(II) hydroxide and hydroxide ion results in the formation of tin(IV) hydroxide.
The balanced molecular equation of the reaction is:
{eq}\displaystyle \rm Sn(OH)_2(s) + 2OH^- (aq) \to Sn(OH)_4(s) {/eq}
The above equation is the balanced net ionic equation for the given reaction.
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Precipitation Reactions: Predicting Precipitates and Net Ionic Equations
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Chapter 10 / Lesson 9
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Study precipitate reactions. Determine precipitate solubility according to solubility rules. Learn to write ionic equations by following a molecular reaction.
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