Why is the stable manifold connected?
Question:
Why is the stable manifold connected?
Diagonalize of Matrix
An {eq}n \times n {/eq} is matrix A is diagonalize if there is an invertible {eq}n \times n {/eq} matrix B such that {eq}{B^{ - 1}}AB {/eq} is a diagonal matrix and iff and only if it has linearly independent eigenvectors. The matrix B is said to diagonalize A.
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View this answerConsider again a real analytic vector field and an equilibrium point , So, {eq}f\left( p \right) = 0{/eq}. Then, p is a hyperbolic equilibrium if...
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Chapter 4 / Lesson 2Matrices are powerful tools for algebra, the building blocks of linear algebra, and workhorses in many fields of mathematics and engineering. This article covers several common classifications of matrices, how they relate to each other, and how to manipulate them.