# When chlorine gas is passed into a hot KOH solution, KClO3 is one of the products. What weight of...

## Question:

When chlorine gas is passed into a hot {eq}KOH {/eq} solution, {eq}KClO_3 {/eq} is one of the products. What weight of {eq}Cl_2 {/eq} is theoretically required to produce 12.3 grams of {eq}KClO_3 {/eq}?

{eq}KOH + Cl_2 \to KClO_3 + H_2O + KCl {/eq}

## Uses of Potassium Chlorate:

Potassium chlorate ({eq}\rm KClO_3 {/eq}) has many uses including:

- Generating oxygen for emergency oxygen masks on aircraft.
- Propellant in some fireworks.
- Reactant in some smoke genades.

## Answer and Explanation: 1

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View this answerWe are asked to calculate the mass of {eq}\rm Cl_2 {/eq} that is needed to produce 12.3 grams of {eq}\rm KClO_3 {/eq} in the following reaction:

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Chapter 9 / Lesson 2Learn about the mole ratio. Understand the definition of mole ratio, how to find mole ratio in stoichiometry, and see examples of using mole ratio in problems.

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