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When 74.4g of calcium and 58.1g of nitrogen gas undergo a reaction that has a 75.1 \% yield, what...

Question:

When {eq}\displaystyle 74.4g {/eq} of calcium and {eq}\displaystyle 58.1g {/eq} of nitrogen gas undergo a reaction that has a {eq}\displaystyle 75.1 \% {/eq} yield, what mass of calcium nitride forms?

Practical Yield


The practical is the actual amount of the substance formed in the experimental process which is divided by the theoretical amount to get the percentage yield of the reaction.

Answer and Explanation: 1

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{eq}3Ca + N_2 \rightarrow Ca_3N_2{/eq}


Given:

Mass of calcium = 74.4 g

Mass of nitrogen = 58.1 g

Percent yield = 75.1%


Firstly we have to...

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Calculating Reaction Yield and Percentage Yield from a Limiting Reactant

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Chapter 9 / Lesson 6
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How to calculate the theoretical yield? Learn the definition and formula of percent yield. Use the theoretical yield equation to calculate theoretical yield.


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