# What would be the concentration of a solution made by diluting 50 mL of a 4.5 M KOH solution to a...

## Question:

What would be the concentration of a solution made by diluting 50 mL of a 4.5 M KOH solution to a volume of 250 mL?

## Dilution:

It was mentioned that dilution was performed for the KOH solution where the initial 50 mL volume was diluted to a volume of 250 mL. It means that the final volume of the solution is 250 mL. The initial and final volume (along with the initial concentration) are all important values to calculate the final concentration after the dilution.

The equation for dilution is:

{eq}\rm C_1V_1=C_2V_2 {/eq}

where:

{eq}\rm C_1 {/eq} is the initial concentration

{eq}\rm V_1 {/eq} is the initial volume

{eq}\rm C_2 {/eq} is the final concentration

{eq}\rm V_2 {/eq} is the final volume

We can now calculate the final concentration of the solution after the dilution.

{eq}\rm C_1V_1=C_2V_2 {/eq}

{eq}\rm \left(4.5\:M\right)\left(50\:mL\times \frac{1\:L}{1000\:mL}\right)=C_2\left(250\:mL\times \:\frac{1\:L}{1000\:mL}\right) {/eq}

{eq}\rm C_2=\frac{\left(4.5\:M\right)\left(50\:mL\times \:\frac{1\:L}{1000\:mL}\right)}{\left(250\:mL\times \:\:\frac{1\:L}{1000\:mL}\right)} {/eq}

{eq}\rm C_2=0.90\:M {/eq}

{eq}\underline{ \rm Conclusion:} {/eq}

The concentration of the solution is equal to 0.90 M.