What volume of a 12.0 M {eq}NH_3 {/eq} solution would be needed to obtain 0.390 moles of {eq}NH_3 {/eq}?

Question:

What volume of a 12.0 M {eq}NH_3 {/eq} solution would be needed to obtain 0.390 moles of {eq}NH_3 {/eq}?

Ammonia:

The chemical formula for ammonia is {eq}\rm N{H_3} {/eq}. It is first synthesized by Joseph Priestley. Some of the areas of application of ammonia is as a fertilizer, pharmaceuticals, metallurgical processes, textile industry, cleansing agents, etc.

Answer and Explanation: 1

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Given data:

  • Molarity of {eq}\rm N{H_3} {/eq} is 12.0 M.
  • Moles of {eq}\rm N{H_3} {/eq} is 0.390 moles.

To find:

  • Volume of...

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Calculating Molarity and Molality Concentration

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Chapter 8 / Lesson 4
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What is molarity? What is molality? Compare molarity vs molality by viewing molality and molarity formulas, how to calculate molarity and molality, and examples.


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