What is the sign of {eq}\displaystyle \rm S {/eq} for the dissolving of {eq}\displaystyle \rm I_2 (s) {/eq} in {eq}\displaystyle \rm CCl_4(l) {/eq}?

## Question:

What is the sign of {eq}\displaystyle \rm S {/eq} for the dissolving of {eq}\displaystyle \rm I_2 (s) {/eq} in {eq}\displaystyle \rm CCl_4(l) {/eq}?

## Entropy:

One of the thermodynamic properties that determine the spontaneity of chemical processes is entropy. This parameter is typically denoted by the variable S. Entropy measures the level of disorderedness of a system. The more disordered the particles in a system are, the higher the entropy.

## Answer and Explanation: 1

In a chemical process, the change in entropy, ΔS, is said to be positive when the final state of the system has a higher entropy than its initial state. Otherwise, ΔS is negative.

When iodine, {eq}\rm I_2
{/eq}, is dissolved in carbon tetrachloride, {eq}\rm CCl_4
{/eq}, the particles of iodine become dispersed in the solvent. From well-organized solid iodine which has less entropy, the dissolution resulted in more disorganized iodine and, hence, an increase in the entropy of the iodine particles. Because of this, it can be said that the **entropy change, ΔS, is positive** because the entropy of the system has increased.

#### Learn more about this topic:

from

Chapter 13 / Lesson 5Understand what entropy change is and learn how to find entropy. Explore the factors that can affect the value of entropy and learn how to predict an entropy change.