What is the product formed when CH_3CH(OH)CH_3 reacted with excess H_2CrO_4 in the presence of...


What is the product formed when {eq}CH_3CH(OH)CH_3 {/eq} reacted with excess {eq}H_2CrO_4 {/eq} in the presence of sulfuric acid?

Oxidation of Alcohols:

Primary alcohols are oxidized to aldehydes, and secondary alcohols are oxidized to ketones. In the presence of strong oxidizing agents, primary alcohols can also be oxidized to carboxylic acids.

Answer and Explanation: 1

Secondary alcohols are oxidized to corresponding ketones on reaction with chromate in presence of sulfuric acid.

The oxidation of propan-2-ol can be summarized by the following reaction:

{eq}CH_{3}CH(OH)CH_{3}+H_{2}CrO_{4}\rightarrow CH_{3}COCH_{3}+HCrO_{3}+H_{3}O^{+} {/eq}

Therefore, propan-2-ol reacts with dichromate in presence of sulfuric acid to form propanone as the major product.

Learn more about this topic:

Oxidation of Alcohols: Mechanism, Reaction & Conditions


Chapter 13 / Lesson 1

Learn about the oxidation of alcohols. Understand oxidation of alcohols mechanisms, oxidation reagents, and see oxidation of propanol and cyclohexanol.

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