What is the {eq}[OH^-] {/eq} of an {eq}0.0025 \ M \ HNO_3(aq) {/eq} solution at {eq}25^\circ C {/eq}?

## Question:

What is the {eq}[OH^-] {/eq} of an {eq}0.0025 \ M \ HNO_3(aq) {/eq} solution at {eq}25^\circ C {/eq}?

## Autoionization of Water:

Water is considered as a very weak electrolyte. Two water molecules one acting as an acid and other as a base react to produce hydronium ion in the solution.

{eq}H_2O (l) +H_2O(l) \leftrightharpoons H_3O^+ + OH^- {/eq}

The autoionization constant of water for every solution is constant at {eq}25^oC {/eq} and is given by {eq}K_w =\displaystyle {[H_3O^+ ][OH^-]} = 1 \times 10^{-14} {/eq}

## Answer and Explanation: 1

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Concentration of {eq}HNO_3 {/eq} is {eq}0.0025 \ M. {/eq}

Now, we write the dissociation reaction of the solution in water

{eq}HNO_3 \...

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Chapter 10 / Lesson 6Learn about the autoionization of water. Understand what the autoionization constant of water is, and explore the Kw constant to determine concentrations of ions.