What is the {eq}[OH^-] {/eq} of an {eq}0.0025 \ M \ HNO_3(aq) {/eq} solution at {eq}25^\circ C {/eq}?


What is the {eq}[OH^-] {/eq} of an {eq}0.0025 \ M \ HNO_3(aq) {/eq} solution at {eq}25^\circ C {/eq}?

Autoionization of Water:

Water is considered as a very weak electrolyte. Two water molecules one acting as an acid and other as a base react to produce hydronium ion in the solution.

{eq}H_2O (l) +H_2O(l) \leftrightharpoons H_3O^+ + OH^- {/eq}

The autoionization constant of water for every solution is constant at {eq}25^oC {/eq} and is given by {eq}K_w =\displaystyle {[H_3O^+ ][OH^-]} = 1 \times 10^{-14} {/eq}

Answer and Explanation: 1

Become a Study.com member to unlock this answer!

View this answer


Concentration of {eq}HNO_3 {/eq} is {eq}0.0025 \ M. {/eq}

Now, we write the dissociation reaction of the solution in water

{eq}HNO_3 \...

See full answer below.

Learn more about this topic:

Dissociation Constant and Autoionization of Water


Chapter 10 / Lesson 6

Learn about the autoionization of water. Understand what the autoionization constant of water is, and explore the Kw constant to determine concentrations of ions.

Related to this Question

Explore our homework questions and answers library