What is the net ionic equation form the reaction between {eq}\rm Na_2S(aq) {/eq} and {eq}\rm Pb(HCO_3)_2(aq) {/eq}?
Question:
What is the net ionic equation form the reaction between {eq}\rm Na_2S(aq) {/eq} and {eq}\rm Pb(HCO_3)_2(aq) {/eq}?
Total and Net Ionic Equations
The total ionic equation shows all the ions present in the reaction, whether or not they are directly involved in the reaction. The net ionic equation, on the other hand, shows all ions that are only directly involved in the reaction. The ions that are not directly involved in the chemical reaction are called spectator ions.
Answer and Explanation: 1
The balanced chemical equation is given by
$$Na_2S \ (aq) + Pb(HCO_3)_2 \ (aq) \to 2 \ NaHCO_3 \ (aq) + PbS \ (s) $$
The total ionic equation is given by
$$2 \ Na^+ \ (aq) + S^{2-} \ (aq) + Pb^{2+} \ (aq) + 2 \ HCO_3^- \ (aq) \to 2 \ Na^+ \ (aq) + 2 \ HCO_3^- \ (aq) + PbS \ (s) $$
Thus, the net ionic equation is given by
$$Pb^{2+} \ (aq) + S^{2-} \ (aq) \to PbS \ (s) $$
Learn more about this topic:
from
Chapter 10 / Lesson 9Study precipitate reactions. Determine precipitate solubility according to solubility rules. Learn to write ionic equations by following a molecular reaction.