What is the molarity of the diluted solution when 0.50 L of a 0.360 M solution of H3PO4 is...
Question:
What is the molarity of the diluted solution when 0.50 L of a 0.360 M solution of {eq}H_3PO_4 {/eq} is diluted to a final volume of 3.00 L?
Diluting a Solution:
The dilution process is achieved by adding more solvent to an existing stock solution. In a dilute solution, the solute particles remain more separated compared to the stock solution. So, the concentration of a stock solution is reduced during dilution.
Answer and Explanation: 1
According to the law of dilution, we can write:
{eq}\rm C_iV_i=C_fV_f {/eq}
- {eq}\rm C_i\;and\;C_f {/eq} represent the initial and final concentrations of a solution, respectively.
- {eq}\rm V_i\;and\;V_f {/eq} represent the initial and final volumes of a solution, respectively.
Given (for {eq}\rm H_3PO_4 {/eq} solution):
{eq}\rm C_i=0.360\;M\\ \rm V_i=0.50\;L\\ \rm V_f=3.00\;L {/eq}
Substituting the above values, we get:
{eq}\rm 0.360\;M\times 0.50\;L=C_f\times 3.00\;L\\ \rm \Rightarrow C_f=0.060\;M {/eq}
Hence, the molarity of the diluted solution is 0.060 M.
Learn more about this topic:
from
Chapter 8 / Lesson 5Want to know how to calculate dilution factor? See dilution equations, the dilution formula, and learn how to dilute acid and how to dilute a solution.