What is the molarity of NaNO by diluting 250.0 mL of a 1.60 M solution to a final volume of 400 cm{eq}^3 {/eq}?

## Question:

What is the molarity of NaNO by diluting 250.0 mL of a 1.60 M solution to a final volume of 400 cm{eq}^3 {/eq}?

## Dilution of Solutions:

A single-step dilution is fairly easy to perform, and equally easy to solve. We can determine the molarity of the diluted solution, {eq}\displaystyle M_2 {/eq}, by multiplying the initial concentration, {eq}\displaystyle M_1 {/eq}, by a dilution factor, {eq}\displaystyle \frac{V_1}{V_2} {/eq}, where {eq}\displaystyle V_1 {/eq} is the initial volume and {eq}\displaystyle V_2 {/eq} is the final volume or the volume of the diluted solution.

## Answer and Explanation: 1

Determine the molarity, {eq}\displaystyle M_2 {/eq}, of the diluted solution by multiplying the initial molarity, {eq}\displaystyle M_1 = 1.60\ M {/eq}, by the dilution constant, {eq}\displaystyle \frac{V_1}{V_2} {/eq}, where {eq}\displaystyle V_1 = 250.0\ mL {/eq} is the initial volume and {eq}\displaystyle V_2 = 400\ cm^3 = 400\ mL {/eq} is the final volume. We proceed with the solution.

{eq}\begin{align} \displaystyle M_2 &= M_1 \times \frac{V_1}{V_2}\\ &= 1.60\ M\times \frac{250.0\ mL}{400\ mL}\\ &= 1\ M \end{align} {/eq}

#### Learn more about this topic:

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Chapter 8 / Lesson 5Want to know how to calculate dilution factor? See dilution equations, the dilution formula, and learn how to dilute acid and how to dilute a solution.