# What is the molarity of a solution that is prepared by diluting 40.0 mL of a 0.200 M Fe2(SO4)3...

## Question:

What is the molarity of a solution that is prepared by diluting 40.0 mL of a 0.200 M {eq}Fe_2(SO_4)_3 {/eq} solution to a volume of 1500 mL?

## Dilution:

If you already have a solution prepared but the experiment or assay requires a solution with a lower concentration, dilution will be done. Here, an aliquot of the prepared solution will be mixed with a particular volume of the solvent. For quantitative purposes, dilution is done using a volumetric flask since a volumetric flask is calibrated to a specific volume.

## Answer and Explanation: 1

The equation that will be used is:

{eq}C1V1 = C2V2 {/eq}

where:

*C1*- concentration of the stock solution**(0.200 M)***V1*- volume of the stock solution**(40.0 mL)***C2*- concentration of the desired solution**(unknown)***V2*- volume of the desired solution**(1500 mL)**

The equation will be rearranged such that the *C2* will be isolated on one side of the equation. With that, the final concentration of the solution will be calculated.

{eq}C2 = \dfrac{C1V1}{V2} {/eq}

{eq}\rm C2 = \dfrac{0.200\ M \times 40.0\ mL}{1500\ mL} = \boxed{\mathbf{5.33 \times 10^{-3}\ M\ fe_2(SO_4)_3}} {/eq}

#### Learn more about this topic:

from

Chapter 8 / Lesson 5Want to know how to calculate dilution factor? See dilution equations, the dilution formula, and learn how to dilute acid and how to dilute a solution.