# What is the molarity of a solution made when you dilute 35 grams of sodium carbonate (Na2CO3) to...

## Question:

What is the molarity of a solution made when you dilute 35 grams of sodium carbonate {eq}(Na_2CO_3) {/eq} to a volume of 3,400 mL?

## Molarity:

The molarity of a solution is evaluated by knowing the solute's mass and the solution's volume. The moles and grams relation is used to convert the mass (in grams) into moles, as shown below.

{eq}n\left( {{\rm{mol}}} \right) = \dfrac{{m\left( {\rm{g}} \right)}}{{{M_{{\rm{Molar}}\;{\rm{Mass}}}}\left( {{\rm{g/mol}}} \right)}} {/eq}

The below formula shows the molarity of a solution.

{eq}M = \dfrac{{n\left( {{\rm{mol}}} \right)}}{{V\left( {\rm{L}} \right)}} {/eq}

Here, the volume of the solution is {eq}V. {/eq}

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Given Data:

• The mass of the sodium carbonate is: {eq}m = 35\;{\rm{g}} {/eq}
• The volume of the solution is: {eq}V = 3400\;{\rm{mL}} {/eq}

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