What is the molarity of {eq}1.8 \ \times \ 10^{4} \ mg {/eq} of {eq}HCl {/eq} in {eq}0.075 \ L {/eq} of solution?

Question:

Molarity Calculations

Suppose that a particular solution consists of the following components:

• The solute of mass {eq}m {/eq} in grams

• The volume of the solution in liters {eq}V {/eq}

• Given the molar mass of the solute {eq}M {/eq}

We can calculate the molarity using the formula

{eq}c = \dfrac{n}{V} {/eq},

where the number of moles, {eq}n {/eq}, is the ratio of the mass of the solute and its molar mass, such that

{eq}n = \dfrac{m}{M} {/eq}.

Answer and Explanation: 1