# What is the concentration of a solution made by diluting 85 mL of 6.0 M HCI to a final volume of...

## Question:

What is the concentration of a solution made by diluting 85 mL of 6.0 M HCI to a final volume of 750 mL?

## Number of Mole:

In chemistry, one of the units representing the amount of either a chemical compound or a single chemical substance is called the mole. Usually, this is determined using the mass and the molar mass. The molarity and volume can also be helpful for determining it. Here, the standard unit of molarity is mole per liter.

Given data

• The volume of the HCl is {eq}{{V}_{1}}=85\ \text{mL}=85\times {{10}^{-3}}\ \text{L} {/eq}
• The molar concentration of HCl is {eq}{{M}_{1}}=6.0\text{M} {/eq}
• The final volume of the prepared solution is {eq}{{V}_{2}}=750\ \text{mL}=750\times {{10}^{-3}}\ \text{L} {/eq}

Now, using given data the concentration (molar concentration) of the solution is computed as,

{eq}\begin{align} {{M}_{1}}{{V}_{1}} &={{M}_{2}}{{V}_{2}} \\ \left( 6.0\ \text{M} \right)\left( 85\times {{10}^{-3}}\ \text{L} \right) &={{M}_{2}}\left( 750\times {{10}^{-3}}\ \text{L} \right) \\ {{M}_{2}} &=\dfrac{\left( 6.0\ \text{M} \right)\left( 85\times {{10}^{-3}}\ \text{L} \right)}{\left( 750\times {{10}^{-3}}\ \text{L} \right)} \\ {{M}_{2}} &=0.68\ \text{M} \end{align} {/eq}

Thus, the concentration of the solution is 0.68 M.