Using the balanced equation of: HCl + NaOH \to H_2O+NaCl, how many moles of HCl could be...

Question:

Using the balanced equation of: {eq}HCl + NaOH \to H_2O+NaCl {/eq}, how many moles of HCl could be neutralized with 13.2 mL of 3.00 M NaOH?

Reaction between HCl and NaOH.

Since hydrochloric acid is a monoprotic acid one mole of hydrochloric acid will be completely neutralized by one mole of sodium hydroxide. The neutralization reaction between hydrochloric acid and sodium hydroxide gives sodium chloride and water.

Answer and Explanation: 1

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Step 1: Determine the moles of NaOH in 13.2 mL of 3.00 M solution of NaOH.

By definition of molarity 1000 mL of the solution contains 3.00 moles of...

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Equivalence Point: Definition & Calculation

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Chapter 12 / Lesson 11
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Learn about equivalence point and end point in titrations. Examine how to find equivalence points in a variety of ways, and discover the steps to do so.


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