Using exactly four 3's and any math symbol, try to write an equivilent expression for each whole...

The expression for {eq}1 {/eq} can be written as,

$$\begin{align} 1= \frac{\left(3+3\right)-3}{3} \end{align} $$

The expression for {eq}2: {/eq}

$$\begin{align} 2= \frac{\left(3\cdot 3\right)-3}{3} \end{align} $$

The expression for {eq}3: {/eq}

$$\begin{align} 3= 3\cdot 3-\left(3+3\right) \end{align} $$

There is impossible to get the expression for {eq}4 {/eq} using the four {eq}3's. {/eq}

Since the expression for {eq}5: {/eq} can be,

$$\begin{align} 5=3+3-\frac{3}{3} \end{align} $$

And the expression for getting {eq}6: {/eq}

$$\begin{align} 6=3+3-\left(3-3\right) \end{align} $$

Expression for getting {eq}7: {/eq}

$$\begin{align} 7=3+3+\frac{3}{3} \end{align} $$

And the expression for {eq}8: {/eq}

$$\begin{align} 8=3\cdot 3-\frac{3}{3} \end{align} $$

The expression for getting {eq}9: {/eq}

$$\begin{align} 9=3\cdot 3-\left(3-3\right) \end{align} $$

And finally the expression for {eq}10: {/eq}

$$\begin{align} 10=3\cdot 3+\left(\frac{3}{3}\right). \end{align} $$