To push a 29.0 kg crate up a frictionless incline, angled at 25.0 degrees to the horizontal, a...
Question:
To push a 29.0 kg crate up a frictionless incline, angled at 25.0{eq}^{\circ} {/eq} to the horizontal, a worker exerts a force of 219 N parallel to the incline. As the crate slides 1.8 m, how much work is done on the crate by (a) the worker's applied force, (b) the gravitational force on the crate, and (c) the normal force exerted by the incline on the crate? (d) What is the total work done on the crate?
Work
Work is a measure assigned to the amount of displacement experienced by a body when a force is applied. Work is a scalar measure and therefore does not have a direction like vector measures. Additionally, it is considered a form of energetic representation of a particle.
Answer and Explanation: 1
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View this answerAccording to the information given,
{eq}\rm \text{Mass} = m = 29.0\ kg\\ \text{Angle} = \theta = 25.0^\circ \\ \text{Force} = F = 219\...
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Chapter 8 / Lesson 3What is work and what is its formula? Learn the definition of work in physics and how to calculate the value of work done by a force using a formula with some examples.
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