# Titration of a 23.0 mL solution of KOH requires 13.0 mL of 0.0250 M H2SO4 solution. What is the...

## Question:

Titration of a 23.0 mL solution of {eq}KOH {/eq} requires 13.0 mL of 0.0250 M {eq}H_2SO_4 {/eq} solution. What is the molarity of the {eq}KOH {/eq} solution?

## Acid and Base Reactions:

The reaction between {eq}NaOH{/eq}, a base and a {eq}HCl{/eq}, an acid proceeds to form a salt, {eq}NaCl{/eq} and {eq}H_2O{/eq}; this is an example of an acid-base reaction. Acid-base reactions are reactions which generally form salt and water as its products. Strong acids and strong bases neutralize each other to produce a solution with a pH value of 7; hence, the term neutralization reaction.

## Answer and Explanation: 1

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Given is the chemical equation for the reaction of {eq}H_2SO_4{/eq} and {eq}KOH{/eq}. Based on this balanced chemical equation, 2 moles of...

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Chapter 11 / Lesson 9Learn about strong acid - strong base titration. Understand strong acid - strong base reactions and how to find an unknown substance concentration, and see the curve.

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