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The molarity of a solution composed of 25.4g {eq}KHCO_3 {/eq} diluted with water to a total volume of 200 mL.

Question:

The molarity of a solution composed of 25.4g {eq}KHCO_3 {/eq} diluted with water to a total volume of 200 mL.

Molarity of a Solution

The number of moles of solute dissolved in a solution which has a volume of one liter, then this measurement for defining concentration term is called molarity of the solution.

Answer and Explanation: 1

We are given:

  • The given mass of potassium bicarbonate in the solution = 25.4 g
  • The volume of the given solution = 200 mL = 0.2 L

We know:

  • The molar mass of potassium bicarbonate = 100 g/mol

Let us find the number of moles of potassium bicarbonate in the solution.

The number of moles of potassium bicarbonate = {eq}\dfrac{25.4\ g}{100\ g/mol}= 0.254\ mol {/eq}

We know that

{eq}\begin{align} \textrm{Molarity of the solution}&=\dfrac{\textrm{Number of moles of potassium bicarbonate}}{\textrm{Volume of solution in liter}}\\ &= \dfrac{0.254\ mol}{0.2\ L}\\ &= 1.27\ M \end{align} {/eq}

Hence, the molarity of the solution is 1.27 M.


Learn more about this topic:

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Calculating Molarity and Molality Concentration

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Chapter 8 / Lesson 4
66K

What is molarity? What is molality? Compare molarity vs molality by viewing molality and molarity formulas, how to calculate molarity and molality, and examples.


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