The integral integral sin^2 8x dx is equal to a. fraction x 2 - fraction sin 16x 32 + C b....


The integral {eq}\displaystyle \int \sin^2 (8x) \ dx {/eq} is equal to

{eq}\text{a.} \ \dfrac{x}{2} - \dfrac{ \sin(16x)}{32} + \text{C} \\ \text{b.} \ \dfrac{x}{2} - \dfrac{ \sin(16x)}{16} + \text{C} \\ \text{c.} \ \dfrac{x}{2}+ \dfrac{ \sin(16x)}{16} + \text{C} \\ \text{d.} \ \dfrac{x}{2}+ \dfrac{ \sin(16x)}{32} + \text{C} {/eq}


To find the area under any curve, integration is used to find the area under that curve.

Use the following formula:

{eq}\sin^2\theta=\frac{1-\cos2\theta}{2} {/eq}

Answer and Explanation: 1

Become a member to unlock this answer!

View this answer

Let {eq}I=\displaystyle \int \sin^2 (8x) \ dx {/eq}.

Use the formula {eq}\sin^2\theta=\frac{1-\cos2\theta}{2} {/eq}.

Put {eq}\theta=8x {/eq}.


See full answer below.

Learn more about this topic:

Integration Problems in Calculus: Solutions & Examples


Chapter 13 / Lesson 13

Learn what integration problems are. Discover how to find integration sums and how to solve integral calculus problems using calculus example problems.

Related to this Question

Explore our homework questions and answers library