# The decomposition of potassium chlorate (KClO_3) is used as a source of oxygen in the laboratory....

## Question:

The decomposition of potassium chlorate ({eq}KClO_3 {/eq}) is used as a source of oxygen in the laboratory. How much potassium chlorate is needed to produce 10.2 mol of oxygen? Answer in units of mol.

## Stoichiometric Number

A stoichiometric equation is one in which the number of elements present on each side is the same. The number that is written before each molecule is the stoichiometric number.

## Answer and Explanation: 1

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- The given mol of oxygen needed to produce is 10.2 mol.

The reaction for the decomposition of {eq}{\rm{KCl}}{{\rm{O}}_{\rm{3}}}{/eq} is shown...

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Chapter 9 / Lesson 2Learn about the mole ratio. Understand the definition of mole ratio, how to find mole ratio in stoichiometry, and see examples of using mole ratio in problems.

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