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The decomposition of potassium chlorate (KClO_3) is used as a source of oxygen in the laboratory....

Question:

The decomposition of potassium chlorate ({eq}KClO_3 {/eq}) is used as a source of oxygen in the laboratory. How much potassium chlorate is needed to produce 10.2 mol of oxygen? Answer in units of mol.

Stoichiometric Number

A stoichiometric equation is one in which the number of elements present on each side is the same. The number that is written before each molecule is the stoichiometric number.

Answer and Explanation: 1

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  • The given mol of oxygen needed to produce is 10.2 mol.


The reaction for the decomposition of {eq}{\rm{KCl}}{{\rm{O}}_{\rm{3}}}{/eq} is shown...

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Mole-to-Mole Ratios and Calculations of a Chemical Equation

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Chapter 9 / Lesson 2
159K

Learn about the mole ratio. Understand the definition of mole ratio, how to find mole ratio in stoichiometry, and see examples of using mole ratio in problems.


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