Suppose you have a solution that might contain any or all of the following cations: Cu2+, Ag+,...
Question:
Suppose you have a solution that might contain any or all of the following cations: Cu{eq}^{2+} {/eq}, Ag{eq}^+ {/eq}, Ba{eq}^{2+} {/eq}, and Mn{eq}^{2+} {/eq}. The addition of NBr causes a precipitate to form. After the precipitate is separated by filtration, H{eq}_2 {/eq}SO{eq}_4 {/eq} is added to the supernatant liquid, and another precipitate forms. This precipitate is separated by filtration, and a solution of NaOH is added to the supernatant liquid until it is strongly alkaline. No precipitate is formed.
(a) Which ions are present in each of the precipitates?
(b) Which cations are not present in the original solution?
Separation of Cations:
Qualitative analysis of the separation of cations may be done by addition of different reagents of different concentrations. Physical changes such as color change of solution, formation of precipitate and effervescence (formation of bubbles) are some of the evidences of confirmation of the presence of different cations. For the formation of precipitate, knowledge of the solubility rules is important.
Answer and Explanation: 1
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View this answerIn a solution where there is a possibility of the presence of the cations {eq}Cu^{2+} {/eq}, {eq}Ag^+ {/eq}, {eq}Ba^{2+} {/eq} and...
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