Suppose that sound is emitted uniformly in all directions by a public address system. The...

Question:

Suppose that sound is emitted uniformly in all directions by a public address system. The intensity at a location 26.4 m away from the sound source is 4.21 x 10{eq}^{-4} {/eq} W/m{eq}^{2} {/eq}. What is the intensity at a spot that is 70.2 m away?

Intensity of Sound:

The Intensity of sound is the power of Sound received per unit area at a location away from sound source. Considering a sound source of power P, Intensity at a distance d from the source, is given by:

{eq}I \ = \dfrac{P}{4\pi d^2} {/eq}

Answer and Explanation: 1

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We are given:

  • Intensity of sound, at distance d = 26.4 m from the source is I = 4.21 x 10{eq}^{-4} {/eq} W/m{eq}^{2} {/eq}

Finding Intensity I ' at...

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Intensity in Physics: Definition & Measurement

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Chapter 5 / Lesson 10
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This lesson explains what wave intensity in physics is, and it explains the intensity of light formula with examples. This lesson also describes how to calculate intensity of sound waves.


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