# Suppose that sound is emitted uniformly in all directions by a public address system. The...

## Question:

Suppose that sound is emitted uniformly in all directions by a public address system. The intensity at a location 26.4 m away from the sound source is 4.21 x 10{eq}^{-4} {/eq} W/m{eq}^{2} {/eq}. What is the intensity at a spot that is 70.2 m away?

## Intensity of Sound:

The Intensity of sound is the power of Sound received per unit area at a location away from sound source. Considering a sound source of power *P*, Intensity at a distance *d* from the source, is given by:

{eq}I \ = \dfrac{P}{4\pi d^2} {/eq}

## Answer and Explanation: 1

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- Intensity of sound, at distance
*d*= 26.4 m from the source is I = 4.21 x 10{eq}^{-4} {/eq} W/m{eq}^{2} {/eq}

**Finding Intensity I ' at...**

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Chapter 5 / Lesson 10This lesson explains what wave intensity in physics is, and it explains the intensity of light formula with examples. This lesson also describes how to calculate intensity of sound waves.

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