Solve the differential equation {eq}y''' - 3y = \cos x {/eq}

Question:

Solution Of The Linear Differential Equation:

The given differential equation second order linear differential equation. There are various methods of solving differential equations. To find the solution of the differential equation first we find the complementry function and particular integral then the general solution of the differential equation will be written as follows.

{eq}y(x)=y_c+y_p{/eq}

To find the particular integral we use following property

{eq}\left [ \frac{1}{f(D^2)}\sin(at)=\frac{1}{f(-a^2)}\sin(at),\: \: f(-a^2)\neq 0\enspace \text{if}\enspace f(-a^2)=0\enspace \text{then}\enspace \frac{1}{f(D^2)}\sin(at)=\frac{x}{f{}'(D)}\sin(at)\right ]\\ {/eq}

Answer and Explanation: 1