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Solve:

{eq}\displaystyle \frac{d \bigg( \cos^ {-1} (\ln \sqrt {t^2 - 2})\bigg)^2} {dt} {/eq}.

Question:

Solve:

{eq}\displaystyle \frac{d \bigg( \cos^ {-1} (\ln \sqrt {t^2 - 2})\bigg)^2} {dt} {/eq}.

Differentiation:

Differentiation is the process of finding derivative.

Derivative is the rate of change of one quantity with respect to other.

For function of function i.e composite function,we have to use chain rule:

{eq}\displaystyle \frac{df\left(u\right)}{dx}=\frac{df}{du}\cdot \frac{du}{dx} {/eq}.

Answer and Explanation: 1

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Given function is

{eq}\displaystyle \frac{d \bigg( \cos^ {-1} (\ln \sqrt {t^2 - 2})\bigg)^2} {dt} {/eq}.

{eq}\displaystyle...

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Using the Chain Rule to Differentiate Complex Functions

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Chapter 8 / Lesson 6
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Learn how to differentiate a function using the chain rule of differentiation. Find various chain rule derivative examples with various function types.


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