In neutralization reactions, acid + base arrow salt + water, HCl can be neutralized with NaOH....
Question:
In neutralization reactions, acid + base {eq}\rightarrow {/eq} salt + water, HCl can be neutralized with NaOH. How many moles of NaOH will it take to neutralize 0.68 L of 0.29 M HCl?
Molarity
The molarity M of a solution is the ratio between the amount of solute n in moles and the volume of the solution V in liters. In mathematical terms,
$$M = \frac{n}{V} $$
Answer and Explanation: 1
Become a Study.com member to unlock this answer! Create your account
View this answerThe neutralization reaction between HCl and NaOH is as follows:
$$HCl \ (aq) + NaOH \ (aq) \to NaCl \ (aq) + H_2O \ (l) $$
First, we calculate the...
See full answer below.
Ask a question
Our experts can answer your tough homework and study questions.
Ask a question Ask a questionSearch Answers
Learn more about this topic:

from
Chapter 8 / Lesson 4What is molarity? What is molality? Compare molarity vs molality by viewing molality and molarity formulas, how to calculate molarity and molality, and examples.
Related to this Question
- How many moles of NaOH are needed to neutralize 15.0 mL of 0.235 M HCl solution?
- How many moles of hydrochloric acid are needed to neutralize 100 mL of 1.0 M NaOH?
- How many moles of NaOH (sodium hydroxide) are required to neutralise 0.52 moles of HCl (hydrochloric acid)?
- 35 ml of a 0.25 m solution of HCl is titrated with an unknown sample of NaOH. How many moles of NaOH are needed to neutralize the HCl solution?
- Using the balanced equation of: HCl + NaOH \to H_2O+NaCl, how many moles of HCl could be neutralized with 13.2 mL of 3.00 M NaOH?
- In the following acid-base reaction, how many mL of 5.0 M NaOH would it take to titrate 750 mL of 3.0 M HCl? NaOH + HCl arrow NaCl + H2O
- 1. In a titration of HCl with NaOH, 100.0 mL of the base was required to neutralize 20.0 mL of 5.0 M HCI. What is the molarity of the NaOH? (Be sure to write the neutralization reaction.)
- For the following neutralization reaction. HClO4(aq) + NaOH(aq) \rightarrow H2O (l) + NaClO4(aq) A) Which one is acid? B) How many moles of acid is needed to neutralize 1 mole of base? C) How many moles HClO4 solution is needed to neutralize 30.00 mL
- For the acid-base reaction (called titration) of sulfuric acid (H2SO4) with sodium hydroxide (NaOH), how many moles of sodium hydroxide would be required to react with 1.03 L of 0.500 M sulfuric acid to reach the complete neutralization (endpoint)?
- How many ml of 0.15 M NaOH solution are required to neutralize 35.00 ml of 0.22 moles of HCl?
- 50 L of 2.0 mol/L Hydrochloric acid is titrated with sodium hydroxide to form water and sodium chloride. How many moles of sodium hydroxide are consumed in this reaction? A. 25 mol. B. 2 mol. C. 100 mol. D. 0.04 mol.
- 38.30 ml of 0.250 molar hydrochloric acid solution reacted exactly with 50.00 ml of a sodium hydroxide solution. A) How many moles of HCl were used? B) How many moles of NaOH reacted? C) What was the molarity of the NaOH?
- For the reaction of hydrochloric acid with magnesium hydroxide. a. How many moles of magnesium hydroxide are required to neutralize one mole of hydrochloric acid? b. If the molarity of the base is 0.100 M, how many mL of base are required to neutralize 10
- How many moles of HCl are needed to completely react with 50.0 mL of 0.250 M NaOH solution?
- Imagine you react HCl (an acid) with NaOH (a base). It requires 25.0 mL of 0.500 M HCl to neutralize a 0.100 M solution of NaOH. How many milliliters of NaOH did you add? A) 0.125 mL. B) 125 mL. C) 0.200 mL. D) 0.0500 mL.
- Imagine you react HCl (an acid) with NaOH (a base). It requires 25.0 mL of 0.500 M HCl to neutralize a 0.100 M solution of NaOH. How many milliliters of NaOH did you add?
- How many mL of a 3.2 M HCl solution would be needed to neutralize 150 mL of 2.6 M NaOH? Both NaOH and HCl are strong acids/bases.
- How many moles of HCl are required to completely react with 50.0 mL of 0.250 M NaOH solution?
- How many moles of NaOH are needed to completely react with 125 mL of a 1.7 M HCl solution?
- 1.9 mol HCl and 3.2 mol NaOH react according to the equation HCl + NaOH rightarrow NaCl + H_2O . Calculate the amount in moles of H_2O formed.
- 1.9 mol HCl and 3.8 mol NaOH react according to the equation HCl + NaOH to NaCl + H_2O. Calculate the amount in moles of NaCl formed. Answer in units of mol.
- How many moles of 1.0m NaOH would be needed to neutralize 250ml of 0.5m HCl?
- For the acid-base titration combination of NaOH with 0.86 mol HCl, find the number of moles of NaOH that would be the chemically equivalent amount of HCl. (Answer in units of mol.)
- 22 mL of NaOH was needed to neutralize acid. How many moles was used?
- In a given experiment 36.44 mL of NaOH were required for neutralize a solution of HCl 0.35 M. Calculate the moles of NaOH present to neutralize the HCl in the titration.
- During a titration of an acid with NaOH, 27.4 moles of a 0.117 M solution were required for neutralization. How many moles of NaOH were dispensed?
- If 10.0 mL of 0.100 M HCl is titrated with 0.200 M NaOH, what volume of sodium hydroxide solution is required to neutralize the acid?
- How many milli-litres of 0.250M NaOH are required to neutralize 30.4mL of 0.146M HCl?
- How many liters of 0.5 M HCl (aq) are needed to neutralize a 288 mL solution of 0.25 M NaOH?
- Find the moles of NaOH used in a titration reaction with HCl if 3.725 mL of 0.1 M NaOH is used to completely react with 4 mL of HCl.
- a. How many moles of NaOH are present in 89.6 mL of 0.714 M NaOH? b. How many moles of HCl are present in a 30.0 mL sample that is neutralized by the 89.6 mL of 0.714 M NaOH? c. What is the molar concentration of the HCl solution described in part (b) of
- How many liters of 1.0 M HCl do you need to neutralize 2.0 L of 3.0 M NaOH?
- A 10.0 ml sample of a HCl solution is titrated with 32.6 ml of a 0.155 M NaOH solution. What is the equation for the neutralization reaction?
- If 5.25 mL of 0.1000 ''M'' NaOH solution is needed to just neutralize excess acid after 20.00 mL of 0.1000 ''M'' HCl was added to 1.00 g of the antacid, how many moles of acid can the antacid counte
- How many mL of 0.49 M HCl will neutralize 42 mL of 1.48 M NaOH?
- When 100.0 mL of 0.100 M HCl solution and 100.0 mL of 0.100 M NaOH are mixed, HCl + NaOH \to NaCl + H_2O 0.0100 mole of HCl reacts completely with 0.0100 mole of NaOH, producing 0.0100 mole of NaCl. Assuming that the amount of water produced by the react
- How many mL of a 0.101 M NaOH solution are required to neutralize 25.0 mL of a 0.119 M HCl solution? HCI + NaOH --> NaCl + H_2O
- How many moles of HCI are needed to completely react with 50.0 mL of 0.250 M NaOH solution?
- Let's say you do a titration of the acid and realize it took you 14.29mL of 0.103 mol/L NaOH(aq) to neutralize all the acid. How many moles of the base did it take?
- Determine the volume of 0.150 M NaOH solution required to neutralize 100 mL of a 9 \times 10^{-2} M HCl solution. The neutralization reaction is NaOH(aq) + HCl(aq) \rightarrow H_2O(l) + NaCl(aq).
- In a acid-base titration, 22.81 mL of an NaOH solution were required to neutralize 26.18 mL of a 0.1121 M HCl solution. What is the molarity of the NaOH solution?
- In an acid-base titration, 22.13 mL of a NaOH solution is needed to neutralize 24.65 mL of a 0.1094 M HCl solution. What is the molarity of the NaOH solution?
- Calculate how many moles of water will be produced given the amount of HCl and NaOH you added. (50
- In a titration reaction, 25 cm3 of 0.1M HCl neutralized 20 cm3 of NaOH. Calculate the concentration of the alkali in moles per litre.
- Volume of HCl = 26.5 mL Volume of NaOH = 29.1 mL Molarity of NaOH = 0.1 mol/L Balanced Equation: NaOH+HCl \rightarrow NaCl+H2O Using the above equation, calculate the number of moles of acid required to react with 2.91 moles of base.
- How many mL of 0.15 M NaOH solution are required to neutralize 35.00 mL of 0.22 M HCl?
- How many mL of 0.36 M NaOH are needed to neutralize 50.00 mL of a 0.150 M solution of HCl?
- Consider the following reaction: HCl (aq) + NaOH (aq) \longrightarrow NaCl (aq) + H_2O (l) Calculate the amount of a 0.215 M NaOH solution required to completely neutralize 3750 mL of 0.195 M HCl solution.
- If 10 mL of 1.0 M HCl are required to neutralize 50 mL of a NaOH solution, how many mL of 1.0 M H_2SO_4 will neutralize another 50 mL of the same NaOH solution?
- How many ml of 0.2m NaOH would be needed to neutralize 100 ml of 0.4m HCl?
- How many ml of 0.0362 M NaOH are needed to neutralize 30.0 ml of 0.0438 M HCl?
- How many mL of 0.100 M NaOH are needed to neutralize 22.0 mL of 0.150 M HCl?
- How many mL of 0.200 M HCl must be added to completely neutralize 30.0 mL of 0.155 M NaOH?
- A solution of baking soda NaHCO_3 prepared from 0.755 g dissolved in 100 mL of water was used as an antacid. 25.00 mL of 0.960 M HCl were used to digest the sample. The volume of 0.595 M NaOH used in the back titration was 6.80 mL. How many moles of HC
- A 21.34 mL sample of 0.1732 M HCl solution requires 28.92 mL of NaOH solution for complete neutralization. a. Calculate the number of moles of NaOH required to completely neutralize the NaOH. b. Calculate the molarity of the NaOH solution.
- How much 1.0 M NaOH would be required to completely neutralize 40.0 mL of 0.60 M HCl?
- How many mL of 0.75 M HCl are needed to neutralize 20.0 grams of NaOH?
- How many ml of 0.20 m NaOH are required to neutralize 100 ml of 5.0 m HCl?
- How many mL of 8.00 M NaOH is required to neutralize 200 mL of 4.00 M HCl?
- How many moles of HCl must have been present in the 25 mL of HCl solution in the two trials? Given: Trial 1: V of HCl = 25.00 mL, V of NaOH used = 29.50 mL, and M of NaOH = 0.18 M Trial 2: V of HCl =
- The reaction of HCl with NaOH is represented by the equation HCl (aq) + NaOH (aq) to NaCl (aq) + H_2O(l). What volume of 0.417 M HCl is required to titrate 11.9 mL of 0.151 M NaOH?
- How many mL of 0.750 M HCl are needed to neutralize 14.89 mL of 0.350 M NaOH?
- How much 0.110 M HCl is required to completely neutralize 10.0 ml of 0.230 M NaOH?
- How much 0.130 M HCl is required to completely neutralize 20.0 ml of 0.200 M NaOH?
- How much 0.100 M HCl is required to completely neutralize 20.0 ml of 0.250 M NaOH?
- How many ml of 3.00 M HCl are required to neutralize 10.0 mL of a 2.00 M NaOH solution?
- Calculate the molarity of HCl and NaOH. Given: HCl volume = 25 mL NaOH = 67.05 mL moles of NaOH = 0.015000 moles
- In a titration, 6.0 moles of NaOH will completely neutralize how many moles of H2SO4?
- You will be mixing 50.0 mL of 2.00 M NaOH with 50.0 mL of 2.00 M HCl. a. How many moles of HCl react? b. How many moles of NaOH react? c. How many moles of water and NaCl will be formed?
- If 20 mL of 1.0 M HCl is used completely to neutralize 40 mL of a NaOH solution, what is the molarity of the NaOH solution?
- If 5.30mL of 0.1000 M NaOH solution is needed to just neutralize excess acid after 20.00 mL of 0.1000 M HCl was added to 1.00 g of an antacid, how many moles of acid can the antacid counteract per gra
- How many grams of NaOH is required to neutralize 25.0 mL of 1.52 M HCl?
- How much of a 0.25 M NaOH solution is needed to neutralize 100 mL of a 0.15 M HCl solution? The units are mL.
- How many milliliters of 1.0 m NaOH would be required to completely neutralize 40.0 ml of 0.60 m HCl?
- How many milliliters of 0.200 M NaOH are required to neutralize 20.0 mL of 0.100 M HCl?
- How many moles of Ba(OH)2 are required to react with 0.179 mol HCl in the following acid-base neutralization? 2HCl(aq) + Ba(OH)2(aq) to BaCl2(aq) + 2H2O(l) a) 1.00 b) 2.00 c) 0.179 d) 0.358 e) 0.0895
- In an acid-base titration, 26.81 mL of a NaOH solution are needed to neutralize 26.98 mL of a 0.1490 M HCl solution. Find the molarity of the NaOH solution.
- If it takes 35.0 mL of a 0.500 M HCl solution to neutralize 245 mL of a NaOH solution, what is the molarity of the NaOH solution?
- How much NaOH which is 25% pure is required to neutralize 100 mL of 10 N HCl?
- You have 14.0 mL of a 0.12 M NaOH solution. How many moles of HCl will it take to neutralize this solution?
- If it takes 50.0 mL of a 0.15 M NaOH solution to neutralize 125.0 mL of an HCl solution, what is the molarity of the HCl solution?
- If it takes 25.0 mL of a 0.400 M NaOH solution to neutralize 20.0 mL of an HCl solution, what is the molarity of the HCl solution?
- How many moles of 0.1 M NaOH were added to the hydrochloric acid? To find the number of moles of NaOH, recall that n= C *V (n is the number of moles, C is concentration, and V is volume). Choose the c
- What is the enthalpy of neutralization for the reaction between solutions of HCl and NaOH?
- Determine the volume of 0.125 M NaOH solution required to neutralize each sample of hydrochloric acid. The neutralization reaction is: NaOH(aq) + HCl(aq) rightarrow H_2O(l) + NaCl (aq) (a) -30 mL of a 0.125 M HCI solution (b) -45 mL of a 0.075 M HCI
- How many milliliters of 0.303 M HCl would be required to exactly neutralize 148 mL of 0.906 M NaOH?
- How many milliliters of 3 M HCl is required to neutralize 0.6 M 50 ml NaOH?
- 19.63 mL of 0.100 M NaOH is required to neutralize 2.00 mL of a solution containing acetic acid according to the following reaction: HC2H3O2 (aq) + NaOH (aq) \rightarrow NaC2H3O2 (aq) + H2O(l). How many moles of NaOH were used in this titration? Report t
- Calculate the amount of 6M HCl necessary to neutralize 3.0 mL of 3M NaOH
- How many moles of water form when 40.0 ml of 0.800 M HNO_3 solution is completely neutralized by NaOH?
- How many milliliters of 0.100 M NaOH are required to neutralize 65.0 mL of 0.250 M H2SO4? The balanced neutralization reaction is: H2SO4(aq)+2NaOH(aq)----->Na2SO4(aq)+2H2O(l).
- Calculate the volume of 0.850-M NaOH solution needed to completely neutralize 25.8 mL of a 0.370-M solution of the monoprotic acid HCl.
- Determine the volume of 0.130 M NaOH solution required to neutralize each sample of hydrochloric acid. The neutralization reaction is: NaOH(aq)+HCl(aq) \rightarrow H_2O(l)+NaCl(aq) a. 35 mL of a 0.130 M HCl solution. b. 50 mL of a 0.075 M HCl solution. c.
- If 2.83 mmol NaOH is added to 50.00mL of 0.118 M hydrochloric acid, how many m moles of hydrochloric acid remain?
- Determine the volume of 0.170 M NaOH solution required to neutralize 25 mL of a 0.170 M HCl solution. NaOH(aq) + HCl(aq) arrow H2O(l) + NaCl(aq)
- Determine the volume of 0.170 M NaOH solution required to neutralize 175 mL of a 0.895 M HCl solution. NaOH(aq) + HCl(aq) arrow H2O(l) + NaCl(aq)
- Determine the volume of 0.170 M NaOH solution required to neutralize 45 mL of a 0.060 M HCl solution. NaOH(aq) + HCl(aq) arrow H2O(l) + NaCl(aq)
- The reaction of HCl with NaOH is represented by the equation HCl (aq) + NaOH (aq) to NaCl (aq) + H_2O(l) What volume of 0.5 M HCl is required to titrate 17.8 mL of 0.3 M NaOH?
- The concentrations of HCl and NaOH solutions used in the neutralization reaction are approximately equivalent, yet the volumes of HCl and NaOH solutions used in the reaction are not equal. Explain why.
- If it requires 30.0 milliliters of 1.2 molar HCl to neutralize 20.0 milliliters of NaOH, what is the concentration of the NaOH solution? Balanced equation: NaOH + HCl to NaCl + H_2O.