# If there are 0.625 g of NaCl left in a beaker that originally contained 75.0 mL of saltwater,...

## Question:

If there are 0.625 *g* of NaCl left in a beaker that originally contained 75.0 *mL* of saltwater, what must have been the molar concentration of the original solution? The molar mass of NaCl is 58.44 *g/mol*.

## Molecular Mass

#### Molecular mass is the sum of the masses of all the atoms in a compound and is usually stated with the units {eq}gmol^{-1} {/eq}. Molecular Mass is used when calculating moles and masses of other compounds.

## Answer and Explanation:

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View this answerFirst we need to find the number of moles of NaCl in the beaker:

{eq}n(NaCl) = \frac{m(NaCl)}{M(NaCl)} = \frac{0.625}{58.44} = 0.01069mol {/eq}

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Calculating Molarity and Molality Concentration

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Chapter 8 / Lesson 4
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What is molarity? What is molality? Compare molarity vs molality by viewing molality and molarity formulas, how to calculate molarity and molality, and examples.

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