If {eq}f(x) = 9 \sqrt{x} (x - 2) {/eq}, find {eq}f'(x) {/eq}.
Question:
If {eq}f(x) = 9 \sqrt{x} (x - 2) {/eq}, find {eq}f'(x) {/eq}.
Differentiation:
Differentiation helps us to calculate a function that is equal to the rate of variation of another function. For example, the velocity function of a moving body is equal to the rate of variation of its position or displacement function. Power rule is an important rule of differentiation, and it states that the differentiation of {eq}{{u}^{n}} {/eq} is {eq}n{{u}^{n-1}} {/eq}.
Answer and Explanation: 1
Become a Study.com member to unlock this answer! Create your account
View this answer
We are given the following function:
{eq}f\left( x \right)=9\sqrt{x}\left( x-2 \right) {/eq}
Simplify the above-given function step-by-step as...
See full answer below.
Learn more about this topic:
from
Chapter 9 / Lesson 8Discover what a second derivative is and how second derivatives can be used to learn more about functions. Observe examples of implicit and explicit second-degree differentiation for linear and parametric functions.