If a string fixed at both ends is vibrating at a frequency of 4.61 Hz and the distance between...
Question:
If a string fixed at both ends is vibrating at a frequency of 4.61 Hz and the distance between two successive nodes is 0.293 m, what is the speed of the waves on the string?
Transverse wave on a string
A transverse wave on a string of wavelength {eq}\lambda {/eq} and frequency {eq}\nu {/eq} can be represented as:
{eq}y \ = \ A \sin (k x \ + \ \omega t ) {/eq}
Where:
{eq}A {/eq} - is the amplitude
{eq}\omega \ = \ 2 \pi \times \nu {/eq} - is the angular frequency
{eq}k \ = \ \dfrac{2 \pi}{\lambda} {/eq} - is the wave number
The speed of the wave {eq}v {/eq}, its frequency {eq}\nu {/eq} and wavelength {eq}\lambda {/eq} are related as: {eq}v \ = \ \nu \times \lambda {/eq}
Answer and Explanation: 1
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View this answerGiven:
- Frequency of oscillation: {eq}\nu \ = \ 4.61 \ H z {/eq}
- Distance between two nodes: {eq}d \ = \ 0.293 \ m {/eq}
If the wavelength of the...
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