If 9.71 mL of 0.252 M KOH is used to completely titrate 15.0 mL of HCl, how many moles of HCl are...

Question:

If 9.71 mL of 0.252 M KOH is used to completely titrate 15.0 mL of HCl, how many moles of HCl are in the solution? Hint: start by writing the balanced chemical equation.

Titration:

In a titration method, a titrant will react with a sample until it reaches the equivalence point. Therefore, it is important to provide a balanced chemical equation that describes the titration reaction. It will show the amount of titrant needed to react with the sample. For the given problem, we need to establish a balanced chemical equation for potassium hydroxide (KOH) and hydrochloric acid (HCl) in order to determine the moles of HCl present in the solution.

Answer and Explanation: 1

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The balanced chemical equation for the titration is:

{eq}KOH\:+HCl\:\rightarrow \:KCl\:+H_2O {/eq}


We need to determine first the moles of KOH...

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Titration of a Strong Acid or a Strong Base

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Chapter 11 / Lesson 9
24K

Learn about strong acid - strong base titration. Understand strong acid - strong base reactions and how to find an unknown substance concentration, and see the curve.


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