If 73.5 mL of 0.200 M potassium iodide solution was required to precipitate all of the lead (II)...
Question:
If 73.5 mL of 0.200 M potassium iodide solution was required to precipitate all of the lead (II) ion from an aqueous solution of lead (II) nitrate, how many moles of lead (II) ion were originally in the solution?
Precipitation Reactions:
We can classify a reaction as a precipitation reaction when we find that an insoluble salt has been formed when mixing two ionic compounds in aqueous solution. Precipitation reactions are double displacement reactions that arise from the exchange of cations and anions. The identity of the precipitate can be predicted by using the solubility rules.
Answer and Explanation: 1
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View this answerThe balanced molecular equation for the precipitation reaction can be written as follows:
{eq}\rm 2KI(aq) + Pb(NO_3)_2(aq) \to PbI_2(s) +...
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Precipitation Reactions: Predicting Precipitates and Net Ionic Equations
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Chapter 10 / Lesson 9
131K
Study precipitate reactions. Determine precipitate solubility according to solubility rules. Learn to write ionic equations by following a molecular reaction.
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