If 4.15 L of a 0.800 M H3PO4 solution is diluted to a volume of 10.00 L, what is the...

Question:

If 4.15 L of a 0.800 M {eq}H_3PO_4 {/eq} solution is diluted to a volume of 10.00 L, what is the concentration of the resulting solution?

Phosphoric Acid:

The compound that has the molecular formula {eq}{{\rm{H}}_3}{\rm{P}}{{\rm{O}}_4} {/eq} is called phosphoric acid. The purest form of this compound appears as a colorless solid. In impure form, this compound is a white solid. For this compound, the molar mass is 98 g/mol.

Answer and Explanation: 1

Given Data:

  • The volume of {eq}{{\rm{H}}_3}{\rm{P}}{{\rm{O}}_4} {/eq} solution before dilution: {eq}{{\rm{V}}_1} = 4.15\;{\rm{L}} {/eq}.
  • The concentration of {eq}{{\rm{H}}_3}{\rm{P}}{{\rm{O}}_4} {/eq} solution before dilution: {eq}{{\rm{M}}_1} = 0.800\;{\rm{M}} {/eq}.
  • The volume of {eq}{{\rm{H}}_3}{\rm{P}}{{\rm{O}}_4} {/eq} solution after dilution: {eq}{{\rm{V}}_2} = 10.00\;{\rm{L}} {/eq}.


To Calculate:

  • The concentration of {eq}{{\rm{H}}_3}{\rm{P}}{{\rm{O}}_4} {/eq} after dilution that is {eq}{{\rm{M}}_2} {/eq}.


The formula is given below.

{eq}{{\rm{M}}_1}{{\rm{V}}_1} = {{\rm{M}}_2}{{\rm{V}}_2} {/eq}

Where,

  • {eq}{{\rm{M}}_1}\;{\rm{and}}\;{{\rm{M}}_2} {/eq} are the concentration before and after dilution respectively.
  • {eq}{{\rm{V}}_1}\;{\rm{and}}\;{{\rm{V}}_2} {/eq} are the volume before and after dilution respectively.


On substituting the corresponding values in the above equation, we get,

{eq}\begin{align*} 0.800\;{\rm{M}} \times 4.15\;{\rm{L}} &= {{\rm{M}}_2} \times 10.00\;{\rm{L}}\\ {{\rm{M}}_2} &= \dfrac{{0.800\;{\rm{M}} \times 4.15\;{\rm{L}}}}{{10.00\;{\rm{L}}}}\\ &= 0.332\;{\rm{M}} \end{align*} {/eq}


Hence, the concentration of the resulting solution is 0.332 M.


Learn more about this topic:

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Calculating Dilution of Solutions

from

Chapter 8 / Lesson 5
93K

Want to know how to calculate dilution factor? See dilution equations, the dilution formula, and learn how to dilute acid and how to dilute a solution.


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