How much potassium chloride in grams is needed to prepare {eq}1500\ ml {/eq} solution of {eq}\rm 3\ M\ KCl {/eq} solution?

## Question:

How much potassium chloride in grams is needed to prepare {eq}1500\ ml {/eq} solution of {eq}\rm 3\ M\ KCl {/eq} solution?

## Molarity:

A quantitative method to express the concentration of a solution is by the use of molarity. The molarity of a solution is defined as the moles of solute per liter of solution.

{eq}Molarity~=~\frac{mol~solute}{liter~solution} {/eq}

## Answer and Explanation: 1

Become a Study.com member to unlock this answer! Create your account

View this answerWe begin by determining the moles of KCl present in 3 M of a 1.5 L solution. ( 1500 mL = 1.5 L)

{eq}mol~KCl~=~(1.5~L)\times(3.00\frac{mol}{L})~=~4.5~...

See full answer below.

#### Learn more about this topic:

from

Chapter 8 / Lesson 4What is molarity? What is molality? Compare molarity vs molality by viewing molality and molarity formulas, how to calculate molarity and molality, and examples.