How much {eq}NaHCO_3 {/eq} (in grams and moles) is needed to make 210.0 mL of a 0.130 M solution?
Question:
How much {eq}NaHCO_3 {/eq} (in grams and moles) is needed to make 210.0 mL of a 0.130 M solution?
Mass and Number of Moles:
Usually, the product of the total available molar concentration and the total available volume of a chemical solution is used to determine their total number of moles. Usually, the product of the total number of moles and the molar mass of a chemical solution is used to determine their mass.
Answer and Explanation: 1
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Given- The total volume of solution is {eq}V=210\ \text{mL}=210\times {{10}^{-3}}\ \text{L} {/eq}, and the molar concentration of the solution is...
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