How many moles of ions will be present in {eq}133 \ ml {/eq} of {eq}0.150 \ M {/eq} solution of sodium chloride {eq}(aq) {/eq}?

## Question:

How many moles of ions will be present in {eq}133 \ ml {/eq} of {eq}0.150 \ M {/eq} solution of sodium chloride {eq}(aq) {/eq}?

## MOLARITY :

The number of moles of a substance in one litre of solution is called its molarity. It is also called as concentration denoted by C.

molarity = moles of solute / volume of solution in litres

C= n/ V

## Answer and Explanation: 1

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- concentration (C)= O.150 mol/L = 0.150 M
- Volume (V) = 133 ml = 0.133 L

we know

{eq}C=\frac{n}{V} \\ n = C \times V {/eq}

substituting...

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Chapter 8 / Lesson 4What is molarity? What is molality? Compare molarity vs molality by viewing molality and molarity formulas, how to calculate molarity and molality, and examples.

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