How many moles of ions will be present in {eq}133 \ ml {/eq} of {eq}0.150 \ M {/eq} solution of sodium chloride {eq}(aq) {/eq}?
Question:
How many moles of ions will be present in {eq}133 \ ml {/eq} of {eq}0.150 \ M {/eq} solution of sodium chloride {eq}(aq) {/eq}?
MOLARITY :
The number of moles of a substance in one litre of solution is called its molarity. It is also called as concentration denoted by C.
molarity = moles of solute / volume of solution in litres
C= n/ V
Answer and Explanation: 1
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- concentration (C)= O.150 mol/L = 0.150 M
- Volume (V) = 133 ml = 0.133 L
we know
{eq}C=\frac{n}{V} \\ n = C \times V {/eq}
substituting...
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