How many liters of a 2.5 M solution can be made using 300 grams of potassium carbonate, {eq}K_2CO_3 {/eq}?
Question:
How many liters of a 2.5 M solution can be made using 300 grams of potassium carbonate, {eq}K_2CO_3 {/eq}?
Potassium Carbonate:
Potassium carbonate is represented by the chemical symbol {eq}{K_2}C{O_3} {/eq}. It is an inorganic compound that is prepared by the reaction of potassium hydroxide with carbon dioxide. It is soluble in water.
Answer and Explanation: 1
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- Molarity of the solution is 2.5 M.
- Mass of the potassium carbonate is 300 g.
- Molecular weight of potassium carbonate is 138.205 g/mol.
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