How many grams of O2 are needed in a reaction that produces 78.0 grams of Na2O? 4Na(s) + O2(g)...

Question:

How many grams of {eq}O_2 {/eq} are needed in a reaction that produces 78.0 grams of {eq}Na_2O {/eq}?

{eq}4Na(s) + O_2(g) \to 2Na_2O(s) {/eq}

Mole:

Mole is an SI unit for the number of moles. The number of moles is defined as the mass of a given substance per unit molecular weight of that substance. The expression for the number of moles is:

$$\boxed{n=\frac{m}{W}} $$

Here:

  • m is the given mass of the substance.
  • W is the molecular weight of the substance.

Answer and Explanation: 1

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Given Reaction:

  • {eq}4Na(s) + O_2(g) \to 2Na_2O(s) {/eq}


  • 78.0 g (m) of {eq}Na_2O {/eq} are given.


The molecular weight of {eq}Na_2O {/eq}...

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Mole Ratio | Definition, Formula & Examples

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Chapter 9 / Lesson 2
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Learn about the mole ratio. Understand the definition of mole ratio, how to find mole ratio in stoichiometry, and see examples of using mole ratio in problems.

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