Helium gas with a volume of 2.60 L under a pressure of 1.30 atm and a temperature of 41.0 degree...
Question:
Helium gas with a volume of 2.60 L under a pressure of 1.30 atm and a temperature of {eq}41.0^{\circ}C {/eq} is warmed until both the pressure and the volume of the gas are doubled. The molar mass of helium is 4.0 g/mol. What is the final temperature of the gas?
a. 1356 K
{eq}b. \ 1751^{\circ}F \\ c. \ 1966^{\circ}C \\ d. \ 983^{\circ}C \\ e. \ 492^{\circ}C {/eq}
Temperature:
The physical property that helps to differentiate between the cold, as well as hot bodies, is termed as temperature. In other words, the temperature can be defined as the measure of the kinetic energy of the particles, which associated with the motion of a particle. The arbitrary scale used to define the temperature of an object is called the temperature scale.
Answer and Explanation: 1
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Given Data:
- The initial volume of helium gas is, {eq}{V_1} = 2.60\;{\rm{L}} {/eq}
- The initial pressure of helium gas is, {eq}{P_1} =...
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