# For research purposes a sonic buoy is tethered to the ocean floor and emits an infrasonic pulse...

## Question:

For research purposes a sonic buoy is tethered to the ocean floor and emits an infrasonic pulse of sound (speed = {eq}1522\ \dfrac m s {/eq}). The period of this sound is {eq}64\ ms {/eq}. Determine the wavelength of the sound.

## Speed of Sound:

Assume a sound wave travels through a channel with a speed {eq}v {/eq}. The frequency and the wavelength of the sound is considered as {eq}\nu {/eq} and {eq}\lambda {/eq}, respectively. In this situation, the speed of the sound is expressed as,

{eq}v = \nu \lambda. {/eq}

## Answer and Explanation: 1

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View this answer**Given data:**

- Speed of sound in water, {eq}v = 1522 \ m/s {/eq}

- Time period of the sound, {eq}T = 64 \ ms = 0.064 \ s {/eq}

The frequency of the...

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Chapter 5 / Lesson 4Learn about the speed of sound and the speed of sound formula and equation. Discover how fast sound travels in different matters and temperatures like water.

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