Find the point on the hyperbola {eq}xy = 8 {/eq} that is closest to the point (3,0).
Question:
Find the point on the hyperbola {eq}xy = 8 {/eq} that is closest to the point (3,0).
Distance Formula
Consider two points {eq}A=(x_0, y_0) {/eq} and {eq}B=(x_1,y_1). {/eq} Then the distance from A to B is given by {eq}d = \sqrt{ (x_1-x_0)^2 + (y_1-y_0)^2}. {/eq} This formula is called the distance formula. The distance formula is related to Pythagorean theorem, if one views a triangle with hypotenuse of AB and legs of lengths {eq}|x_1-x_0| {/eq} and {eq}|y_1-y_0|. {/eq}
Answer and Explanation: 1
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View this answerConsider the hyperbola {eq}xy=8. {/eq} There are a many ways to determine the point on the hyperbola that is the closed to {eq}(3,0). {/eq} A...
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Chapter 1 / Lesson 7How is distance defined? Learn about what distance is and how to use the distance formula.