# Find the particular solution of the differential equation that satisfies the initial condition....

## Question:

Find the particular solution of the differential equation that satisfies the initial condition.

{eq}\displaystyle \dfrac {dy} {dx} = \dfrac 1 {\sqrt {36 - x^2}},\ y (0) = \pi {/eq}

## Solving the Particular Solution of a Differential Equation:

When solving a differential equation, we get the general solution wherein a constant of integration is added. If we substitute the initial value condition, we can obtain the value of this constant of integration. The solution we get in doing so is called the particular solution.

## Answer and Explanation: 1

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View this answerWe need to get the particular solution of the given differential equation that satisfies the initial condition.

$$\dfrac{\text{d}y}{\text{d}x} =...

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Chapter 16 / Lesson 1Discover what separable differential equations are and their uses. Learn to identify if an equation is separable and how to solve them through given examples.

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