# Find the mass percent of CuSO_4 in a solution whose density is 1.30 g/mL and whose molarity is...

## Question:

Find the mass percent of CuSO{eq}_4{/eq} in a solution whose density is 1.30 g/mL and whose molarity is 1.36 M.

## Molarity and Mass Percentage :

Molarity is defined as the number of moles of solute per liter of solution. It is given as:

{eq}\rm Molarity = \dfrac{n}{Volume(liter)} {/eq}

where *n* = number of moles of solute and *V* = volume of solution in liters.

It is represented as M.

Mass percentage, another concentration unit, is given as:

{eq}\rm \dfrac{M_{a}}{M_{a}+M_{b}}{/eq} where the numerator represents the mass of solute and denominator represents mass of solution.

## Answer and Explanation: 1

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We can calculate the mass of solution using the density as following :

{eq}\rm 1.30\;g/mL = \dfrac{m}{1000\;mL} {/eq}

This gives m = 1300 g.

The...

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Chapter 8 / Lesson 4What is molarity? What is molality? Compare molarity vs molality by viewing molality and molarity formulas, how to calculate molarity and molality, and examples.