Find the general solution of the differential equation. x^2y'' + xy' + 4y = sin(2 ln x) cos(2 ln...
Question:
Find the general solution of the differential equation.
{eq}x^2y'' + xy' + 4y = \sin(2 \ln x) \cos(2 \ln x), \ \ x > 0 {/eq}.
Non-Homogeneous 2nd Order Linear ODEs:
Given a non-homogeneous 2nd Order Linear ODE of the form
{eq}a(x)y'' + b(x) y'+ c(x) y = f(x) {/eq}
have a solution that is composed of a homogeneous solution {eq}y_h {/eq} and a particular solution {eq}y_p {/eq}.
The homogeneous solution {eq}y_h {/eq} takes the form
{eq}y_h = c_1 y_1 + c_2 y_2 {/eq}
where {eq}c_1 {/eq} and {eq}c_2 {/eq} are constants and {eq}y_1 {/eq} and {eq}y_2 {/eq} are two independent solutions to the homogeneous problem:
{eq}a(x)y'' + b(x) y'+ c(x) y = 0 {/eq}.
The particular solution contains no undetermined constants and solves the original problem such that the general solution of the problem is
{eq}y = y_h + y_p {/eq}.
Answer and Explanation: 1
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View this answerTo find the homogeneous solution to this problem, I will guess a function of the form {eq}c x^p {/eq}. Plugging this into the homogeneous ODE, we...
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Chapter 16 / Lesson 3Learn to define what a linear differential equation and a first-order linear equation are. Learn how to solve the linear differential equation. See examples.