Find the following integral.

{eq}\displaystyle \int \frac{\sqrt{(\tan x)^2 - 2}}{\cos^2 x} \ dx {/eq}


Find the following integral.

{eq}\displaystyle \int \frac{\sqrt{(\tan x)^2 - 2}}{\cos^2 x} \ dx {/eq}

Integration by Substitution:

In calculus, integration or anti-differentiation works opposite operation what differentiation does. In the substitution method of integration, the derivative of the substituted functions is already given in the integrand. It is used to rewrite the complex integrand into a simpler expression that can be easily integrated.

Some integral formulas for special functions are given below:

{eq}\begin{align*} \int {\sqrt {{x^2} - {a^2}} dx} &= \dfrac{x}{2}\sqrt {{x^2} - {a^2}} - \dfrac{{{a^2}}}{2}\ln \left| {x + \sqrt {{x^2} - {a^2}} } \right| + C\\ \int {\sqrt {{x^2} + {a^2}} dx} &= \dfrac{x}{2}\sqrt {{x^2} + {a^2}} + \dfrac{{{a^2}}}{2}\ln \left| {x + \sqrt {{x^2} + {a^2}} } \right| + C\\ \int {\sqrt {{a^2} - {x^2}} dx} &= \dfrac{x}{2}\sqrt {{a^2} - {x^2}} + \dfrac{{{a^2}}}{2}{\sin ^{ - 1}}\left( {\dfrac{x}{a}} \right) + C \end{align*} {/eq}

Answer and Explanation: 1

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Given Data:

  • The given integral is: {eq}I = \int {\dfrac{{\sqrt {{{\left( {\tan x} \right)}^2} - 2} }}{{{{\cos }^2}x}}dx} {/eq}.

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Learn more about this topic:

U Substitution: Examples & Concept


Chapter 12 / Lesson 13

In this lesson, learn the technique of integration by u-substitution, its step-by-step method, and see different examples.

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