# Find the area of the surface generated by revolving the given curve about the x-axis. y = 6x; 0...

## Question:

Find the area of the surface generated by revolving the given curve about the {eq}x {/eq}-axis.

{eq}y = 6x; \ \ 0 \leq x \leq 1 {/eq}

## Surface Area:

Surface area is generated with the help of the area of a circle.

First, we differentiate the given curve.

Here, the order of integration is {eq}x=0{/eq} and {eq}x=1{/eq}.

The given curve is a polynomial function so it is quite easy for us to differentiate and integrate.

## Answer and Explanation: 1

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Given:

• The given curve is {eq}y=6x{/eq}; {eq}0\le x\le 1{/eq}.

Surface area of the solid generated when the curve is revolving about the...

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