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Find the area of the surface generated by revolving the given curve about the x-axis. y = 6x; 0...

Question:

Find the area of the surface generated by revolving the given curve about the {eq}x {/eq}-axis.

{eq}y = 6x; \ \ 0 \leq x \leq 1 {/eq}

Surface Area:


Surface area is generated with the help of the area of a circle.

First, we differentiate the given curve.

Here, the order of integration is {eq}x=0{/eq} and {eq}x=1{/eq}.

The given curve is a polynomial function so it is quite easy for us to differentiate and integrate.

Answer and Explanation: 1

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Given:


  • The given curve is {eq}y=6x{/eq}; {eq}0\le x\le 1{/eq}.


Surface area of the solid generated when the curve is revolving about the...

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Integration Problems in Calculus: Solutions & Examples

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Chapter 13 / Lesson 13
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Learn what integration problems are. Discover how to find integration sums and how to solve integral calculus problems using calculus example problems.


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