Find {eq}{f}'(x) {/eq} for {eq}\displaystyle f(x) = \frac{-x^{3}}{3} + 144x {/eq}
Question:
Find {eq}{f}'(x) {/eq} for {eq}\displaystyle f(x) = \frac{-x^{3}}{3} + 144x {/eq}
Differentiation:
We will differentiate each term of given function with respect to x to find its derivative. The following formula of differentiation will be applicable:
{eq}\begin{align} \frac{d}{dx}x^n& =nx^{n-1}& \left[\text{Power rule of differentiate } \right]\\ \\ \end{align} {/eq}
Answer and Explanation: 1
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View this answer{eq}\begin{align} f(x) &= \frac{-x^{3}}{3} + 144x\\ \Rightarrow f'(x)&= \frac{d}{dx} \left[ \frac{-x^{3}}{3} + 144x \right]\ &...
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Chapter 8 / Lesson 34Learn about differentiated instruction in math. Discover examples of instructional strategies and examine ways to optimize differentiation in the math classroom.