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Find {eq}{f}'(x) {/eq} for {eq}\displaystyle f(x) = \frac{-x^{3}}{3} + 144x {/eq}

Question:

Find {eq}{f}'(x) {/eq} for {eq}\displaystyle f(x) = \frac{-x^{3}}{3} + 144x {/eq}

Differentiation:

We will differentiate each term of given function with respect to x to find its derivative. The following formula of differentiation will be applicable:

{eq}\begin{align} \frac{d}{dx}x^n& =nx^{n-1}& \left[\text{Power rule of differentiate } \right]\\ \\ \end{align} {/eq}

Answer and Explanation: 1

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{eq}\begin{align} f(x) &= \frac{-x^{3}}{3} + 144x\\ \Rightarrow f'(x)&= \frac{d}{dx} \left[ \frac{-x^{3}}{3} + 144x \right]\ &...

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How to Differentiate Math Instruction

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Chapter 8 / Lesson 34
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Learn about differentiated instruction in math. Discover examples of instructional strategies and examine ways to optimize differentiation in the math classroom.


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